3n 5 86+5n Answer

Then transpose the numbers. So the answer is. 3n-5=-8(6+5n) 3n-5 = -48-40n 43n = -43 n = -1 ===== Cheers,.

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3n-5=-8(6+5n) - The first step is to use the distributive property to get rid of those parentheses.

3n 5 86+5n answer. LOGIN TO VIEW ANSWER. Apply the distributive property. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Solve for n 3n-5=-8(6+5n) Simplify. -5 + 3n = -8 (6 + 5n) -5 + 3n = (6 * -8 + 5n * -8) -5 + 3n = (-48 + -40n) Solving -5 + 3n = -48 + -40n Solving for variable 'n'. Solve for n 3n-5=-8(6+5n) Simplify.

3n-5=-8(6+5n) 3n-5 = -48 - 40n 43n = -43 n=-1. 37n= -43----- -----37 37. Tap for more steps.

Tap for more steps. Tap for more steps. Move all terms containing n to the left, all other terms to the right.

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Answer by stanbon(757) (Show Source):. Apply the distributive property.

The product of two consecutive odd integers is 77 more than twice the larger integer.find the integers. Related Questions in Mathematics. Tap for more steps.

Solution for 3n-5=-8 (6+5n) equation:. LOGIN TO POST ANSWER. Please post your answer:.

30/06/19 05:57 PM. 3n-5= -8(6 + 5n) so:. Simplifying 3n + -5 = -8 (6 + 5n) Reorder the terms:.

You can put this solution on YOUR website!. This video discusses how to solve an equation for a variable which is a. In this math video lesson on Multi-Step Equations I solve the equation 3n-5=-8(6+5n).

3n-5=-48-40n - The next step is to get the variables on one side of the equation.

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$\\Solution:\\\\ \text{Let the first terms } a_1,\ \ a_2 \ \ \text{ and the common differences } d_1,\ d_2 \ \text{ of first and second APs respectively} \\\\ Sum\ of\ n\ the\ terms\ in\ 1^{st}\ AP=\frac{n}{2}(2a_1+(n-1)d_1)\\\\\\ Sum\ of\ n\ the\ terms\ in\ 2^{nd}\ AP=\frac{n}{2}(2a_2+(n-1)d_2)\\\\\\ \text{Given: Ratio of the sums of n terms of two AP}=\frac{3n+4}{5n +6}\\\\\\ \Rightarrow \frac{\frac{n}{2}(2a_1+(n-1)d_1)}{\frac{n}{2}(2a_2+(n-1)d_2)}=\frac{3n+4}{5n +6}\\\\\\ \Rightarrow \frac{2a_1+(n-1)d_1}{2a_2+(n-1)d_2}=\frac{3n+4}{5n +6}\\\\\\ \Rightarrow \frac{a_1+(\frac{n-1}{2})d_1}{a_2+(\frac{n-1}{2})d_2}=\frac{3n+4}{5n +6}\ \ \ \ \rightarrow (1)\\\\\\ Let,\ \frac{n-1}{2}=m-1\\\\ \Rightarrow n-1=2(m-1)\\\\ \Rightarrow n=2m-2+1\\\\ \Rightarrow n=2m-1\\\\ Substitute\ above\ values\ in\ equation\ (1)\\\\ \Rightarrow \frac{a_1+(m-1)d_1}{a_2+(m-1)d_2}=\frac{3(2m-1)+4}{5(2m-1)+6}$

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$\\\Rightarrow \frac{T_{m1}}{T_{m2}}=\frac{6m-3+4}{10m-5+6}\\\\\\ \Rightarrow \frac{T_{m1}}{T_{m2}}=\frac{6m+1}{8m+1}\\\\\\ \therefore m^{th}\ terms\ ratio\ of\ two\ AP's=\frac{6m+1}{8m+1}\\\\ Now,\\\\ \text{Ratio of 5th terms of tw AP's }=\frac{6\times5+1}{8\times5+1}=\frac{30+1}{40+1}=\frac{31}{41}$

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3n 5 86+5n Answer

3n-5=-8(6+5n) - The first step is to use the distributive property to get rid of those parentheses.

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